Calculation of wall pressure bearing capacity of seamless steel pipe

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For seamless steel tubes, the outer diameter and wall thickness are known, and it is required to calculate how much pressure it can withstand; or the known outer diameter
 
And pressure, it is required to calculate its economical wall thickness. In the above two situations, our designers are at work.
 
Often encountered, here, to provide you with a formula:
 
Set the tensile strength of the material to σ, the pressure to P, and the outer diameter of the tube D;
 
Pipe wall thickness δ=( P*D )/(2* σ/S)
 
Where S is the safety factor;
 
The pressure P is less than 7MPa , S=8 ; P is 7 to 17.5MPa , S=6 ; P is greater than 17.5MPa , S=4 ;
 
For example: See φ16*3 seamless steel pipe (20# steel), how much pressure can it withstand?
 
seamless steel pipe
 
Our first step is to choose the safety factor.
 
S=6; the tensile strength of 20# steel is 410MPa;
 
 
 
Φ 16*3 Seamless steel tube withstand pressure:
 
P= (2* σ /S* )δ/D
 
=(2*410/6*3)/16
 
 
 
=25.6MPa
 
--------- This value > 17.5MPa
 
 
 
Therefore, the safety factor is taken for the second time S=4
 
Φ 16*3 Seamless steel tube withstand pressure:
 
P= (2* σ /S* )δ/D
 
=(2*410/4*3)/16
 
=38.4MPa
 
 
 
The real case of our design
 
:
 
 
 
1. For a project, the GL heater mixed water pipe adopts φ76*4 seamless steel pipe (20# steel):
 
 
 
Our first step is to choose the safety factor
 
S=6; the tensile strength of 20# steel is 410MPa;
 
 
 
The pressure that the steel tube can withstand P= (2* σ/S* δ)/D
 
=(2*410/6*4)/76
 
 
 
=7.2MPa
 
(This value is between 7 and 17.5 MPa)
 
 
 
Conclusion: φ 76*4 seamless steel tube can withstand the project
 
2.2MPa steam pressure, don't worry.
 
 
 
2. For the same project mentioned above, the GL heater heat exchange tube is initially selected as φ 18*2.5 seamless steel tube, which is not used.
 
Usually used φ18*2 seamless steel pipe (20# steel), then, φ18*2 seamless steel pipe can withstand 2.2MPa
 
What about steam pressure?
 
 
Our first step is to choose the safety factor.
 
S=8; the tensile strength of 20# steel is 410MPa;
 
 
 
The pressure that the steel tube can withstand P= (2* σ/S* δ)/D
 
=(2*410/8*2)/18
 
 
 
=11.4MPa
 
-------- This value > 7MPa
 
 
 
Therefore, the safety factor is taken for the second time S=6
 
The pressure that the steel tube can withstand P= (2* σ/S* δ)/D
 
 
 
 
 
 
=(2*410/6*2)/18
 
=15.2MPa
 
It can be seen that φ 18*2 seamless steel pipe can be pressed
 
 
 
 
 
15.2MPa, the steam pressure in the project is
 
 
 
2.2MPa, for this condition, it is not necessary to use φ 18*2.5 (the wall thickness is increased, the pressure bearing capacity will be higher).
 
.

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